an object weighing 200 lbs. and suspended by a rope A is pulled asisde by the horizontal rope B and held so that rope A makes an angle of 30 degree with the vertical. find the tensions in rope A and B.
2 answers
do it yourself
30o W. of N. = 120o CCW from + x-axis.
The system is in equilibrium:
A*Cos120 = - B*Cos (0).
A = -B*Cos(0)/Cos120 = 2B.
A*sin120 = -(-200),
A = 200/sin120 = 231 Lbs.
A = 2B, 231 = 2B, B = 115.5 Lbs.
The system is in equilibrium:
A*Cos120 = - B*Cos (0).
A = -B*Cos(0)/Cos120 = 2B.
A*sin120 = -(-200),
A = 200/sin120 = 231 Lbs.
A = 2B, 231 = 2B, B = 115.5 Lbs.
1 answer