I can help you with C:
You have height, acceleration (9.81), and initial velocity (0) so you use:
Vf ^2 = Vi^2 + 2gh
A 5kg ball is dropped from a height of 10m
a) find the initial potential energy of the ball
B. Find the kinetic energy of the ball just before it reaches ground.
C. Calculate the velocity before it reaches the ground.
4 answers
B. PE = M*g*h Joules.
B. KE = PE =
C. V^2 = Vo^2 + 2g*h = 0 + 19.6*10 = 196, V = 14 m/s.
B. KE = PE =
C. V^2 = Vo^2 + 2g*h = 0 + 19.6*10 = 196, V = 14 m/s.
Correction:
A. PE = M*g*h Joules.
A. PE = M*g*h Joules.
a) potential energy=mgh =5*9.8*10=490j b)kinetic energy=1/2mv^2=0 hope it help
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