A 51 kg person drinks 330. g of milk, which has a "caloric" value of approximately 3.0 kJ/g. If only 18% of the energy in milk is converted to mechanical work, how high (in meters) can the person climb based on this energy intake? [Hint: The work done in ascending is given by mgh, where m is the mass (in kilograms), g the gravitational acceleration (9.8 m/s2), and h the height (in meters.)]

Answer 1

330 g x 3.0 kJ/g x 0.18 = ?? kJ.
Substitute into mgh for work and solve for h

Answer 2

It says that answer is off by a multiple of ten.