How much energy is in the 490 g milk?
3 kJ/g x 43,000 g x 0.16 = ??
E = mgh. Solve for h.
A 43 kg person drinks 490 g of milk, which has a "caloric" value of approximately 3.0 kJ/g. If only 16% of the energy in milk is converted to mechanical work, how high (in meters) can the person climb based on this energy intake? [Hint: The work done in ascending is given by mgh, where m is the mass (in kilograms), g the gravitational acceleration (9.8 m/s2), and h the height (in meters.)]
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DrBob is WRONG according to my gd assignment
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