A 50g sample of metal was heated to 100 degrees Celsius and then dropped into a beaker containing 50g of water at 25 degrees Celsius. If the specific heat of the metal is .25 cal/g degrees Celsius, what is the final temperature of the water?

A. 27
B. 40
C. 60
D. 86
(units are degrees Celsius)

I don't know how to go about solving this. Help please?

Thank you

3 answers

heat lost by metal + heat gained by water = 0

[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat water x (Tfinal-Tinitial)] = 0
Substitute and solve for Tfinal, the only unknown.
Sample of gas is heated from 25c to 55c it will expand by
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