A 125-g piece of metal is heated to 288 degrees celsius and dropped into 85.0 g of water at 26 degrees celsius. If the final temperature of water and metal is 58 degrees celsius, what is the specific heat of the metal?

Answer 1

heat lost by metal + heat gained by water = 0
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Substitute the numbers and solve for the only unknown, the specific heat of the metal.

Answer 2

0.38J|g○C

Answer 3

700

Answer 4

9.76g

Answer 5

0.129 J/g C