A 50 gram glass holds 400 grams of liquid water and 75 grams of ice. After 20 minutes the mass of ice is 50 grams. In 1-2 sentences, assuming no evaporation or sublimation has occurred, calculate the mass of the liquid water at this time and explain how this is found. (no plagiarism)

1 answer

At the end of 20 minutes, the mass of liquid water is 425 grams, calculated by adding the initial mass of the liquid water (400 grams) to the mass of the melted ice (50 grams), which accounts for the loss of 25 grams of ice that melted. Therefore, the total mass of liquid water is the original water amount plus the amount of ice that turned to liquid.