A 50 gram glass holds 400 grams of liquid water and 75 grams of ice. After 20 minutes the mass of ice is 50 grams. In 1 sentences, assuming no evaporation or sublimation has occurred, calculate the mass of the liquid water at this time and explain how this is found.(2 points)

Answer 1

At the end of 20 minutes, the mass of the liquid water is 425 grams, which is calculated by adding the initial mass of liquid water (400 grams) to the mass of melted ice (50 grams) and subtracting the mass of the remaining ice (25 grams), resulting in 400 grams + (75 grams - 25 grams) = 425 grams.