After 20 minutes, the mass of the liquid water is 425 grams. This is found by adding the initial mass of the liquid water (400 grams) to the initial mass of ice (75 grams) and then accounting for the melted ice, resulting in a total mass of 400 grams (liquid water) + 50 grams (melted ice) = 450 grams, and since the total mass remains constant and no water is lost, the liquid water is 425 grams (after accounting for the 50 grams of ice that melted into the liquid).
A 50 gram glass holds 400 grams of liquid water and 75 grams of ice. After 20 minutes the mass of ice is 50 grams. In 1-2 sentences, assuming no evaporation or sublimation has occurred, calculate the mass of the liquid water at this time and explain how this is found.(2 points)
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