A 50 g bullet travelling with an initial velocity of 400 m/s penetrates into a wall with an average force of 4*10^4 N.It goes out of the wall with a velocity of 50 m/s. What is the thickness of the wall

Answer 1

Initial ke = (1/2)(.05)(400)^2
Final Ke = (1/2)(.05) (50)^2

so work done = (1/2)(.05)( 400^2-50^2)
= force * distane = 40,000 T
solve for T