.050 Vo = 1.050 v
so
v = .0476 Vo
initial Ke = (1/2)(.05)Vo^2
final Ke = (1/2)(1.05)v^2
100 (.05 Vo^2 - 1.05 v^2) /.05 Vo^2
100 (.05 Vo^2 - .00238 Vo^2)/.05 Vo^2
= 95.2 % of initial energy is lost
A 50 g ball of clay traveling at speed v0 hits and sticks to a 1.0 kg block sitting at rest on a frictionless surface.
A) What is the speed of the block after the collision?
B) What percentage of the ball's initial energy is "lost"?
1 answer
2 answers