A 50.0g ball of clay traveling east at 3.00 m/s collides and sticks

together with a 50.0g ball of clay traveling north at 3.50m/s.
What is the speed and direction of the resulting ball of clay?

2 answers

initial east momentum = 150
initial north momentum = 175

final mass = 100 g

initial east momentum = final
so
final east = 150 = 100 u
u = 1.5

initial north momentum = final
so
final north = 175 = 100 v
v = 1.75

speed = sqrt (1.5^2+1.75^2)

tan angle n of e = 1.75/1.5
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