Work for changing KE of cyclist+bicycle is
W=Δ KE= KE2 –KE1=
=3000-750 = 2250 J,
for the cyclist:
W1=ΔKE1 = m1•v2^2/2 – m1•v1^2/2 =
=50•100/2-50•25/2 =1875 J,
for the bicycle:
W2=ΔKE2 = m2•v2^2/2 – m2•v1^2/2 =
=10•100/2 - 10•25/2 =375 J
A 50.0kg cyclist on a 10.0kg bicycle speeds up from 5.0m/s to 10.0m/s , the total kinetic energy before acceleratingis 750, and after acceleratingis 3000, how much work is done to increase the kinetic energy of the cyclist and the bicycle
8 answers
I am 4 years in the future
dude same
me too
We could also use:
50.0 10.0
I am 9 years in the future :) so cool
i am 10 years in the future <3