a. 5(z + 1) = 3(z + 2) + 11 Solve for Z

Question

b. 7(x+4)-2[x-3(5+x)]=2/3(x-6)

Answer 1

Who are all those different "Sofa's" ?

You must know how to do these simple equations,
show me your first few steps, so I can see where your difficulties are

Answer 2

It's my sisters

Answer 3

a. 5z + 1= 3z + 2 + 11 i think i get this question but i don't understand b.

Answer 4

No, you don't get a)

here is what you should have:
5(z + 1) = 3(z + 2) + 11
5z + 5 = 3z + 6 + 11
5z - 3z = 17 - 5
2z = 12
z = 6

b)
7(x+4)-2[x-3(5+x)]=2/3(x-6)
inner brackets first
7(x+4)-2[x-15-3x]=2/3(x-6)
simplify and do the front while at it
7x + 28 - 2[-2x - 15] = 2/3(x-6)
do the square bracket
7x + 28 + 4x + 30 = 2/3(x-6)
simplify the left
11x + 58 = 2/3(x-6)
multiply every term by 3 to clear that fraction
33x + 174 = 2(x-6)
33x + 174 = 2x - 12
33x - 2x = -12 - 174
31x = -186
divide both sides by 31
x = -6

Once you understand how to do these, and have done about 50 of them,
you can really reduce the number of steps to about 4

Answer 5

thank you