A 5.84kg box sits on a ramp that is inclined at 35.2degrees above the horizontal. The coefficient of kinetic friction between the box and the ramp is 0.27. What horizontal force is required to move the box up the incline with a constant acceleration of 4.30m/s square

Answer 1

N=m•g•cosα+F•sinα
ma=F•cosα-F(fr)-mgsinα =
=F•cosα - μN- mgsinα=
= F•cosα – μ(m•g•cosα+F•sinα) - mgsinα,
ma = F•cosα – μ•m•g•cosα - μ•F•sinα - mgsinα,
F• (cosα -μ•sinα) = m(a+g•sinα+μ•g•cosα),
F= m(a+g•sinα+μ•g•cosα)/ (cosα -μ•sinα).