A 5.84 box sits on a ramp that is inclined at 35.2 above the horizontal. The coefficient of kinetic friction between the box and the ramp is 0.27. What horizontal force is required to move the box up the incline with a constant acceleration of 4.30 ?
3 answers
Dimensions must be provided with your numbers.
A 5.84kg box sits on a ramp that is inclined at 35.2degrees above the horizontal. The coefficient of kinetic friction between the box and the ramp is 0.27. What horizontal force is required to move the box up the incline with a constant acceleration of 4.30m/s square
N=m•g•cosα+F•sinα
ma=F•cosα-F(fr)-mgsinα =
=F•cosα - μN- mgsinα=
= F•cosα – μ(m•g•cosα+F•sinα) - mgsinα,
ma = F•cosα – μ•m•g•cosα - μ•F•sinα - mgsinα,
F• (cosα -μ•sinα) = m(a+g•sinα+μ•g•cosα),
F= m(a+g•sinα+μ•g•cosα)/ (cosα -μ•sinα).
ma=F•cosα-F(fr)-mgsinα =
=F•cosα - μN- mgsinα=
= F•cosα – μ(m•g•cosα+F•sinα) - mgsinα,
ma = F•cosα – μ•m•g•cosα - μ•F•sinα - mgsinα,
F• (cosα -μ•sinα) = m(a+g•sinα+μ•g•cosα),
F= m(a+g•sinα+μ•g•cosα)/ (cosα -μ•sinα).