W(fr) = F(fr) •s=μ•mg•cosα•s=0.305•5.2•9.8•cos13°•1.57 =
W(gr) = m•g•h=m•g•s•sinα=5.2•9.8•1.57•sin13° = …
W(norm) =N•s•cos90°=0
A 5.20 package slides 1.57 down a long ramp that is inclined at 13.0 below the horizontal. The coefficient of kinetic friction between the package and the ramp is = 0.305
Calculate the work done on the package by friction.
Calculate the work done on the package by gravity.
Calculate the work done on the package by the normal force.
1 answer
1 answer