A package slides down a 135 m long ramp with no friction. If the package starts from rest at the top and is to have a speed no faster than 19m/s at the bottom, what should be the maximum angle of inclination?

Answer 1

(1/2) M Vmax^2 = M*g*135 sinA

M cancels out.

sinA = (1/2)Vmax^2/(g*135)
= 0.1364
A = 7.84 degrees