a 5.00g sample of Al pellets (specific heat=0.89J/oC*g) and a 10.00g sample of Fe pellets (specific heat=0.45J/oC*g) are heated to 100.0oC. The mixture of hot iron Al is then dropped into 92.1g of water at 21.8oC. Calculate final temp of metal and water mixture, assuming no heat loss to surroundings.

Question

how do I even start this and what equation would I use?

are there any good sites that have plenty of example problems with solutions for an observation learner?

Answer 1

I don't know of a site. Two things you need to know.
heat lost + heat gained = 0
and
mass x specific heat x delta T = heat lost or gained by anything.

so.
heat lost by Al + heat lost by Fe + heat gained by water = 0
heat lost by Al = mass x specific heat x (Tf - Ti) where Tf is final T and Ti is initial T.

heat lost by Fe = mass x specific heat x (Tf - Ti).

heat gained by water = mass x specific heat x (Tf - Ti)

You know mass Fe, Al, and water.
You know specific heat Fe, Al and water.
You know initial T (Ti) of Fe, Al, and water.
Tf for all are the same. Solve for Tf. That's the only unknown.

Answer 2

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Answer 3

Which has the largest capacity of heat? aluminum 150g, iron 250g, and lead 350g