The sum of the heats gained is zero (so will be absorbing heat, so will be negative heat gain).
HeatgainedAl + heatgainedFe + heatgainedwater=0
HeatgainedAl= massAl*Ca*(tf-100)
heat gainedFe=massFe*Cfe*(tf-100)
heatgainedwater=masswater*ch2o*(tf-22)
solve for tf.
A 5.00 g sample of Al pellets (specific heat = .89 J/g degrees c) and a 10.00 g sample of Fe pellets (specific heat = .45 J/g degrees c) are heated to 100.0 degrees C. The mixture of hot Fe and Al is then dropped into 97.3 g of water at 22.0 degrees C. Calculate the final temp of the metal and water mixture, assuming no heat is lost to surroundings.
how do i do this problem? i'm completely lost.
2 answers
how do i solve for tf if there's nothing on the other side of the equal sign?