A 5.00 kg howler monkey is swinging due east on a vine. It overtakes and grab onto a 6.00 kg monkey also moving east on a second vine. The first monkey is moving at 12.0 m/s at the instant I grabs the second, which is moving at 8.00 m/s. After they join on the same vine, what is their common speed?

Answer 1

Use the following relationship:

M1V1 +M2V2= M3V3

Where

M1=5.00kg
V1=12.0m/s
M2=6.00kg
V2=8.00m/s
M3=5.00kg+6.00kg=11.00kg
and
V3=???

Solve for V3:

(5.00kg*12.0m/s)+(6.00kg*8.00m/s)=(11.00kg)V3

V3=108kg*m/s/11.00kg

V3=9.82 N s

Answer 2

V3=9.82m/s