A 455-g chunk of iron is removed from an oven and plunged into 385g water in an insulated container. The temperature of the water increases from 27 degrees celsius to 89 degrees celsius.

Question

If the specific heat of iron is 0.449 J g^-1 degrees Celsius^-1, what must have been the original temperature of the iron?

Answer 1

heat lost by the iron + heat gained by water = 0.

[massFe x specific heatFe x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tinitial)] = 0
Only one unknown, Tinitial Fe.

Answer 2

How do I figure out the final Fe?

Answer 3

How do you find out the final Fe