Asked by Angel

A 455-g chunk of iron is removed from an oven and plunged into 385g water in an insulated container. The temperature of the water increases from 27 degrees celsius to 89 degrees celsius.

If the specific heat of iron is 0.449 J g^-1 degrees Celsius^-1, what must have been the original temperature of the iron?

Answers

Answered by DrBob222
See your post above.
Answered by Dee
[massFe x specific heatFe x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tinitial)] = 0
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