A 45 kg person jumps off a diving platform 10.0 m above the water. If they reach the surface of the water at a speed of 12 ms, whatis the person's kinetic energy? Hint: Use the formula KE = ‡mo?. (3 points)

1 answer

To find the person's kinetic energy, we can use the formula KE = 1/2 * m * v^2, where KE is the kinetic energy, m is the mass of the person, and v is the speed at which they reach the surface of the water.

Given:
m = 45 kg
v = 12 m/s

Plugging in the values into the formula, we get:

KE = 1/2 * 45 kg * (12 m/s)^2
= 1/2 * 45 kg * 144 m^2/s^2
= 1/2 * 45 kg * 144 m^2/s^2
= 3240 kg * m^2/s^2

Therefore, the person's kinetic energy is 3240 kg * m^2/s^2.