A 45 kg person jumps off a diving platform 10.0 m above the water. If they reaches the surface of the water at a speed of 12 m/s, what is the person’s kinetic energy? Hint: Use the formula KE=½ mv2(3 points)

1 answer

The formula for kinetic energy is KE=½ mv², where m is the mass of the object and v is the velocity of the object.

Given:
m = 45 kg (mass of the person)
v = 12 m/s (speed of the person)

Substituting the given values into the formula, we get:
KE = ½ (45 kg) (12 m/s)²
= ½ (45 kg) (144 m²/s²)
= 0.5 (45 kg) (144 m²/s²)
= 0.5 (6480 kg m²/s²)
= 3240 kg m²/s²

Therefore, the person's kinetic energy is 3240 kg m²/s².