Question

A 42kg girl jumps on a trampoline, after stretching to its bottom limit; the trampoline exerts an average upward force on the girl over a diplacement of 0.50m. During the time that the trampoline is pushing her up, se experiences an average acceleration of 65.0m/s^2. Her velocity at the moment that she leaves the trampoline is 9.4m/s[up]
a) What is the average force that the trampoline exerts on the girl?
b) How much high does she bounce?

Answer 1

avgforce*distance=1/2 mass*velocity^2
solve for avgforce.

How high?
1/2 mass*velocity^2=mass*gh
or 1/2 velocity^2/g= height