Asked by DJ
A 55 kg trampoline artist jumps vertically upward from the top of a platform with a speed of 5.5 m/s. (Ignore small changes in gravitational potential energy.)
(a) How fast is he going as he lands on the trampoline, 3.0 m below?
(b) If the trampoline behaves like a spring of spring constant 5.2 104 N/m, how far does he depress it?
(a) How fast is he going as he lands on the trampoline, 3.0 m below?
(b) If the trampoline behaves like a spring of spring constant 5.2 104 N/m, how far does he depress it?
Answers
Answered by
Anonymous
find total height
h=(1/2)v^2*g
plug into equation v=sqrt(2*9.8*total height) that's velocity
h=(1/2)v^2*g
plug into equation v=sqrt(2*9.8*total height) that's velocity
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