a .415 kg baseball is pitched at 42 m/s. the batter hits it horizontally to the pitcher at 58 m/s.

a) find the change in momentum of the ball.

b) if the ball and bat were in contact for 4.6*10^-4 s what would be the average force while they touched?

1 answer

changemomentum=mass*changevelocty=
= mass*(vf-vi)=mass(-58-42)

force*time=change of momentum
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