I got all but this problem, I

A 0.145-kg baseball is pitched at 42.0 m/s. The batter hits it horizontally to the pitcher at 58 m/s.

A. Find change in momentum? Is it =.145*58-(-.145*42)=1.45-kg m/s?

B. If bat and ball are in contact for 4.6 x 10-4 s, what is average force during contact?

1 answer

A. To find the change in momentum, we use the formula:

Change in momentum = m(vf - vi)

where m is the mass of the baseball, vf is the final velocity, and vi is the initial velocity.

Change in momentum = 0.145 kg * (58 m/s - (-42 m/s))

Change in momentum = 0.145 kg * (100 m/s)

Change in momentum = 14.5 kg*m/s

B. To find the average force during contact, we use the formula:

Average force = (change in momentum) / (time in contact)

Average force = (14.5 kg*m/s) / (4.6 x 10^-4 s)

Average force = 31521.74 N

So, the average force during contact is approximately 31,522 N.