let b = specific heat of brass
410 * s * (95.0 - 32.0) = 335 * 4.18 * (32.0 - 25.0)
A 410-g cylinder of brass is heated to 95.0°C and placed in a calorimeter containing 335 g of water at 25.0°C. The water is stirred, and its highest temperature is recorded as 32.0°C. From the thermal energy gained by the water, determine the specific heat of brass. The specific heat of water is 4.18J/g*C. Show your work.
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