All you have to do is look up the coefficents of linear expansion,subtract one from the other, then
deltaL=L(differenceincoefficents)
a bimetallic compound strip of brass and iron is 10cm long at 20C. When heated over a Bunsen burner flame the temperature of the brass rises to 800C and the iron to 750C. Calculate the difference in lengths of the iron and brass. (Ignore the bending effect)...please help
7 answers
oops, multiply that by delta Temp.
i don't exactly understand what you are saying
Cynthia from Assumption! HEY! (if it's not you ignore this...)Oh that one is linear expansion we didn't do that lol :P
From
Linear expansivity= ∆L/L∆Q
For Brass = L2 - 10/10(800-20)
There fore = 10.14742cm
For iron the same way
= 10.07446cm
∆L = 10.14741- 10.07446
= 0.07296
Linear expansivity= ∆L/L∆Q
For Brass = L2 - 10/10(800-20)
There fore = 10.14742cm
For iron the same way
= 10.07446cm
∆L = 10.14741- 10.07446
= 0.07296
From
Linear expansivity= ∆L/L∆Q
For Brass = L2 - 10/10(800-20)
There fore = 10.14742cm
For iron the same way
= 10.07446cm
∆L = 10.14741- 10.07446
= 0.07296cm
Linear expansivity= ∆L/L∆Q
For Brass = L2 - 10/10(800-20)
There fore = 10.14742cm
For iron the same way
= 10.07446cm
∆L = 10.14741- 10.07446
= 0.07296cm
From
Linear expansivity= ∆L/L∆Q
For Brass = L2 - 10/10(800-20)
There fore = 10.14742cm
For iron the same way
= 10.07446cm
∆L = 10.14741- 10.07446
= 0.07296cm
Linear expansivity= ∆L/L∆Q
For Brass = L2 - 10/10(800-20)
There fore = 10.14742cm
For iron the same way
= 10.07446cm
∆L = 10.14741- 10.07446
= 0.07296cm
1 answer