Asked by cynthia
a bimetallic compound strip of brass and iron is 10cm long at 20C. When heated over a Bunsen burner flame the temperature of the brass rises to 800C and the iron to 750C. Calculate the difference in lengths of the iron and brass. (Ignore the bending effect)...please help
Answers
Answered by
bobpursley
All you have to do is look up the coefficents of linear expansion,subtract one from the other, then
deltaL=L(differenceincoefficents)
deltaL=L(differenceincoefficents)
Answered by
bobpursley
oops, multiply that by delta Temp.
Answered by
cynthia
i don't exactly understand what you are saying
Answered by
Amanda Touf
Cynthia from Assumption! HEY! (if it's not you ignore this...)Oh that one is linear expansion we didn't do that lol :P
Answer
From
Linear expansivity= ∆L/L∆Q
For Brass = L2 - 10/10(800-20)
There fore = 10.14742cm
For iron the same way
= 10.07446cm
∆L = 10.14741- 10.07446
= 0.07296
Linear expansivity= ∆L/L∆Q
For Brass = L2 - 10/10(800-20)
There fore = 10.14742cm
For iron the same way
= 10.07446cm
∆L = 10.14741- 10.07446
= 0.07296
Answer
From
Linear expansivity= ∆L/L∆Q
For Brass = L2 - 10/10(800-20)
There fore = 10.14742cm
For iron the same way
= 10.07446cm
∆L = 10.14741- 10.07446
= 0.07296cm
Linear expansivity= ∆L/L∆Q
For Brass = L2 - 10/10(800-20)
There fore = 10.14742cm
For iron the same way
= 10.07446cm
∆L = 10.14741- 10.07446
= 0.07296cm
Answered by
Meshack Madata
From
Linear expansivity= ∆L/L∆Q
For Brass = L2 - 10/10(800-20)
There fore = 10.14742cm
For iron the same way
= 10.07446cm
∆L = 10.14741- 10.07446
= 0.07296cm
Linear expansivity= ∆L/L∆Q
For Brass = L2 - 10/10(800-20)
There fore = 10.14742cm
For iron the same way
= 10.07446cm
∆L = 10.14741- 10.07446
= 0.07296cm
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