A 400 N object is hanging from two ropes that are suspended from the ceiling. One of the ropes forms a 60° angle with the ceiling and has a tension of 400 N. Calculate the tension in the second rope

Answer 1

the horizontal components of the two ropes' tensions balance each other

the combined vertical components equal 400 N

sin(60º) = T1v / 400 N

T2v = 400 N - T1v

cos(60º) = T1h = T2H

T2 = √[(T2v)² + (T2h)²]