The first step is to use the conservation of momentum to solve for the velocities of the two marbles after the collision. Momentum is conserved, meaning that the total momentum before the collision must equal the total momentum after the collision.
The momentum of the first marble before the collision is 40 g x 2.3 m/s = 92 g m/s. The momentum of the second marble before the collision is 0 g m/s.
The total momentum before the collision is 92 g m/s.
The momentum of the first marble after the collision is 40 g x V1, where V1 is the velocity of the first marble after the collision. The momentum of the second marble after the collision is 29 g x V2, where V2 is the velocity of the second marble after the collision.
The total momentum after the collision is 40 g x V1 + 29 g x V2 = 92 g m/s.
Solving for V1 and V2, we get:
V1 = 2.3 m/s
V2 = 3.2 m/s
A 40 g marble moving at 2.3 m/s strikes a 29 g marble at rest. Assume the collision is perfectly elastic and the marbles collide head-on. What is the speed of the first marble immediately after the collision? What is the speed of the second marble immediately after the collision?
How do you set this up?
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