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A 40.0-mL sample of 0.100 M HNO2 is titrated with 0.200 M KOH. Calculate the volume required to reach the equivalence point (in mL)

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HNO2 + KOH ==> KNO2 + H2O
mols HNO2 = M x L = ?
mols KOH = mols HNO2 from the balanced equation.
Then M KOH = mols KOH/L KOH.
You know M and mol KOH, solve for L and convert to mL.

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