A 4.90 g nugget of pure gold absorbed 255 J of heat. What was the final temperature of the gold if the initial temperature was 24.0°C? The specific heat of gold is 0.129 J/(g·°C).
3 answers
q = mass Au x specific heat Au x (Tfinal-Tinitial)
463.5342
YOU CAN USE ALGEBRA!
energy absorbed=given grams x specific heat x (unknown final temperature-initial temp)
SO:
255=4.90(.129)(x-24)
255=0.6321(x-24)
DIVIDE BOTH SIDES BY .6321
.6321(255)=(.6321(x-24))/,6321
403.42 = x-24
+24 +24
----------------
x=427.42
energy absorbed=given grams x specific heat x (unknown final temperature-initial temp)
SO:
255=4.90(.129)(x-24)
255=0.6321(x-24)
DIVIDE BOTH SIDES BY .6321
.6321(255)=(.6321(x-24))/,6321
403.42 = x-24
+24 +24
----------------
x=427.42
1 answer