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YOU CAN USE ALGEBRA! energy absorbed=given grams x specific heat x (unknown final temperature-initial temp) SO: 255=4.90(.129)(x-24) 255=0.6321(x-24) DIVIDE BOTH SIDES BY .6321 .6321(255)=(.6321(x-24))/,6321 403.42 = x-24 +24 +24 ---------------- x=427.42
