A 4.86 kg sample of a solution of the solute chloroform in the solvent (C2H5)2O that has a concentration of 1.91 pph by mass chloroform is available. Calculate the amount (g) of CHCl3 that is present in the sample.

Question

A 4.86 kg sample of a solution of the solute chloroform in the solvent (C2H5)2O that has a concentration of 1.91 pph by mass chloroform is available. Calculate the amount (g) of CHCl3 that is present in the sample. 
Molar Mass (g/mol) 
CHCl3 119.38 
(C2H5)2O 74.12 
 
Density (g/mL):  
CHCl3 1.483 
(C2H5)2O 0.7138 
 
Name/Formula: 
chloroform 
CHCl3 
diethyl ether 
(C2H5)2O

DrBob222 · Answer

pph = parts per hundred = %. 1.91 pph = 1.91% 4.86 kg = 4860 g sample; of which there is 1.91% CHCl3. Therefore, the amount of CHCl3 is 4,860 g x 0.0191 = ?? Check my thinking. Check my work.

robie miranda · Answer

5. The tetraethyl lead [Pb(C2H5)4] in a 25.00-mL sample of aviation gasoline was shaken with 15.00mL of 0.02095M I2