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A 4.00 kg block is accelerated along a level surface at 3.00 m/s^2. The applied force is 20.0 N.

What is the coefficient of friction between the block and the surface?

2 answers

f = m a ... 20 + x = 4 * 3 ... x = -8

friction = m g μ ... 8 = 4 * g * μ

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