Asked by tally
A 4.0-m-long steel wire has a cross-sectional area of 0.050cm2. Its proportional limit has a value of 0.0016 times its Young's modulus. Its breaking stress has a value of 0.0065 times its Young's modulus. The wire is fastened at its upper end and hangs vertically.
A. How great a weight can be hung from the wire without exceeding the proportional limit? Take the Young's modulus for the rod to be Y=2.0×1011Pa.
B. How much will the wire stretch under this load?
A. How great a weight can be hung from the wire without exceeding the proportional limit? Take the Young's modulus for the rod to be Y=2.0×1011Pa.
B. How much will the wire stretch under this load?
Answers
Answered by
Mitch
A) F = 0.0016YA, F= 1600N
B) Delta L = FL/AY, Delta L = 0.0064 m or 6.4 mm
C) F = 0.0065YA, F = 6500N
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Just did this problem and it's correct, I got'chu.
B) Delta L = FL/AY, Delta L = 0.0064 m or 6.4 mm
C) F = 0.0065YA, F = 6500N
-----------------------------------------
Just did this problem and it's correct, I got'chu.
Answered by
lost
thank you!
Answered by
Anonymous
How great a weight can be hung from the wire without exceeding the proportional limit? Take the Young's modulus for the rod to be Y=2.0×1011Pa.
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