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A 37.0-kg crate rests on a level floor. A horizontal force of 50.0 N accelerates the crate at 1.00 m/s2.

Calculate the frictional force on the crate.

Calculate the coefficient of kinetic friction between the crate and the floor.

I got the normal force, 363 N. Now just need help with these two following problems. Please and thank you!

1 answer

50-friction=37*1
friction=13 N
13=mu*37*9.8

mu= 13/(37*9.8)

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