50-friction=37*1
friction=13 N
13=mu*37*9.8
mu= 13/(37*9.8)
A 37.0-kg crate rests on a level floor. A horizontal force of 50.0 N accelerates the crate at 1.00 m/s2.
Calculate the frictional force on the crate.
Calculate the coefficient of kinetic friction between the crate and the floor.
I got the normal force, 363 N. Now just need help with these two following problems. Please and thank you!
1 answer