A 36-kg girl is bouncing on a trampoline. During a certain interval after she leaves the surface of the trampoline, her kinetic energy decreases to 185 J from 460 J. How high does she rise during this interval? Neglect air resistance.

Answer 1

m*g = 36 * 9.8 = 352.8 N.

KE+PE = 460 J.
185 + PE = 460
PE = 275 J. = mg*h
mg*h = 275
352.8h = 275

h = 0.779 m.