What's the molarity of the HCl?
1.18 g/mL x 1000 mL x 037 x (1 mol/36.5g) = ? M
Then mL1 x M1 = mL2 x M2
a 35.0ml sample of 37% hcl solution has a density of 1.18g/ml. the sample is diluted to a volume of 0.125L. what is the molarity of the final solution ?
3 answers
DrBob222 i need the solution of this numerical problem step by step please
John, I did everything but draw a picture and we can't draw pictures on this forum.
The first part is 1.18 x 1000 x 0.37 x (1/36.5) = APPROXIMATELY 12 M but you do the math yourself and use your number.
Then
35.0 = mL1
12 = M1
125 = mL2
M2 = unknown
35.0 x 12 = 125 mL x M2
Solve for M2 of the diluted solution.
Your answer should be about 3.5M.
The first part is 1.18 x 1000 x 0.37 x (1/36.5) = APPROXIMATELY 12 M but you do the math yourself and use your number.
Then
35.0 = mL1
12 = M1
125 = mL2
M2 = unknown
35.0 x 12 = 125 mL x M2
Solve for M2 of the diluted solution.
Your answer should be about 3.5M.