300cal=5000gwater*1cal/gramC*deltatemp
solve for delta temp.
A 300 Calorie donut is used to heat 5.0 kg of water. If the initial temperature of the water is 20 degrees C what will the final temperature of the water be? Assume no heat loss to the surroundings
2 answers
Where does the 1cal/gramC come from???
1 answer