A 30-kg child stands at one end of a floating 20-kg canoe that is 5.0-m long and initially at rest in the water. The child then slowly walks to the other end of the canoe. How far does the canoe move in the water, assuming water friction is negligible?

Answer 1

the center of mass remains at the same place.

As I do this in my head, cm at start measureing from the center of the canoe, (20*0+30*2.5)/50=7/5 m from the center of the boat. So it shifts then to that far on the other side, so the boat moved 14/5 meters relative to the water.

Answer 2

Thanks,.following your work(20*0+30*2.5)/50

I got 1.5 then I doubled and got 3m.

Answer choices we're:
1m 2m 3m 4m 5m