A man with a mass(mm) of 71.9 kg stands up in a 95-kg canoe(mc) of length(l) 4.00 m floating on water. He walks from a point 0.75 m from the back of the canoe to a point 0.75 m from the front of the canoe. Assume negligible friction between the canoe and the water. How far does the canoe move?

Answer 1

No external forces on system so center of mass continues at constant speed of zero so does not move

how far did he walk in the canoe?
4.00 - 1.5 = 2.5 m

distance he moved * his mass = distance canoe moved * its mass

2.5 *71.9 = 95 x

x = 2.5 * 71.9 / 95