A 3 m long wire carrying a current of 1 A through a magnetic field of magnitude 17 T experiences a force of 8 kN entirely due to the current passing through the magnetic field. what angle does the wire make with the magnetic field?

Answer 1

sinA = F/(B*I*L) = 8000/(17*1*3)

solve for angle A

Since A has a sine > 1, something is wrong with this question. With that B field and currint, a force that large is not possible. Are you sure you copied the problem correctly?

Answer 2

The problem is the notation. That is not kilo-newtons, that is k hat newtons. it should be 8/(17*1*3)