In this situation,
F = B I L
where L is the length of the wire.
Therefore,
B = F/(IL)
You got the correct number. The units are Teslas (T)
A current-carrying wire is oriented at right angles to a uniform magnetic field. If the length of the wire is
0.50 m and it experiences a force of 0.90 N while carrying a current of 4.0 A, what is the strength of the magnetic field?
I did the work and got:
0.45 ...???
2 answers
yes, 0.45 T thanks for checking!
4 answers