A 3.40 kg block is pushed along the ceiling with an constant applied force of F = 82.0 N that acts at an angle θ = 50° with the horizontal, as in the figure below. The block accelerates to the right at 5.80 m/s2. Determine the coefficient of kinetic friction between the block and the ceiling. μk =

Answer 1

Use F = m*a and solve for the friction coefficient, which will be part of the Force term.

[82cos50 - (82sin50-3.40*g)*ìk]
= 3.40*5.8

The term in brackets [ ] is the net force along the ceiling.