A 4 kg block is pushed along the ceiling with a constant applied force of 85 N that acts at an angle of 55 degrees with the horizontal. The block accelerates to the right at 6 m/s^2. determine the coefficient of kinetic friction between the block and the ceiling.
The applied force in the direction of motion is 85 cos 55 = 48.75 N
The friction force that acts opposite to the direction of motion is
(F sin55 - M g)* (mu,k)
To solve for (mu,k), the coefficient of kinetic friction, solve the Newton's Second Law equation
Fnet = F cos55 -F sin55 + M g(mu,k]
= M a
You already know F, M, g and a.
4 answers
1.14
3.55
4.00 kg block is pushed along
the ceiling with a constant
applied force of 85.0 N that acts
at an angle of 55.0° with the
horizontal, as in the figure. The block accelerates to the right at 6.00 m/s2. Determine the coefficient of kinetic friction between the block and the ceiling.
the ceiling with a constant
applied force of 85.0 N that acts
at an angle of 55.0° with the
horizontal, as in the figure. The block accelerates to the right at 6.00 m/s2. Determine the coefficient of kinetic friction between the block and the ceiling.
4.00 kg block is pushed along
the ceiling with a constant
applied force of 85.0 N that acts
at an angle of 55.0° with the
horizontal, as in the figure. The block accelerates to the right at 6.00 m/s2. Determine the coefficient of kinetic friction between the block and the ceiling.
the ceiling with a constant
applied force of 85.0 N that acts
at an angle of 55.0° with the
horizontal, as in the figure. The block accelerates to the right at 6.00 m/s2. Determine the coefficient of kinetic friction between the block and the ceiling.
1 answer