A 3.00 - µF and a 4.00 - µF capacitor are connected in series, and this combination is connected in parallel with a 2.00 - µF capacitor (see the figure ). What is the net capacitance?

Question

3.00 - µF 4.00 - µF

2.00 - µF

26.0 V

Answer 1

For the two caps in series, 1/C = 1/3 + 1/4
C = 12/7

For the two caps now in parallel, C = 2 + 12/7 = 26/7 = 3.71

Answer 2

Thank you Steve!

Answer 3

2.0
4th